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Groovy > 基準日からの連続した日付を得る

date-seq.groovy

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22 for(int i=0;i<10;i++){
	showDate(2013,1,30+i)
}	
def showDate(int yy,int mm, int dd){
	def youbi = ["Sunday"
			,"Monday"
			,"Tuesday"
			,"Wednesday"
			,"Thursday"
			,"Friday"
			,"Saturday"]
	Calendar cal = Calendar.getInstance()
	cal.set(yy,mm-1,dd)
	y = cal.get(Calendar.YEAR)
	m = cal.get(Calendar.MONTH) + 1
	d = cal.get(Calendar.DATE)
	w = cal.get(Calendar.DAY_OF_WEEK)-1
	h = cal.get(Calendar.HOUR_OF_DAY)
	min = cal.get(Calendar.MINUTE)
	sec = cal.get(Calendar.SECOND)
	printf("%04d-%02d-%02d %s\n" ,y ,m ,d ,youbi[w])
}

$ groovy date-seq.groovy
2013-01-30 Wednesday
2013-01-31 Thursday
2013-02-01 Friday
2013-02-02 Saturday
2013-02-03 Sunday
2013-02-04 Monday
2013-02-05 Tuesday
2013-02-06 Wednesday
2013-02-07 Thursday
2013-02-08 Friday
$

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