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Bash > 基準日からの連続した日付を得る
dateseq.bash
for i in `seq 0 9`;do date +"%F %A" --date "20130111 $i days";done
$ source dateseq.bash
2013-01-11 Friday
2013-01-12 Saturday
2013-01-13 Sunday
2013-01-14 Monday
2013-01-15 Tuesday
2013-01-16 Wednesday
2013-01-17 Thursday
2013-01-18 Friday
2013-01-19 Saturday
2013-01-20 Sunday
$
2013-01-11 Friday
2013-01-12 Saturday
2013-01-13 Sunday
2013-01-14 Monday
2013-01-15 Tuesday
2013-01-16 Wednesday
2013-01-17 Thursday
2013-01-18 Friday
2013-01-19 Saturday
2013-01-20 Sunday
$